Calculate the closest distance a 9 MeV alpha particle can approach the target nucleus of an...
Calculate the closest distance a 9 MeV alpha particle can approach the target nucleus of an Fe atom for a potential direct head-on impact. How does this value compare with the radius of the Fe nucleus? Does the alpha touch the nucleus?
Homework Answers
Given:
Kinetic energy of alpha particle
Positive charge contained in an alpha particle 
Positive charge contained in an iron nucleus 
Solution:
Let the distance of closest approach is 
.
The kinetic energy of the alpha particle will be converted into the potential energy of the alpha particle and iron nucleus at the distance of closest approach.
Radius of the iron nucleus is 
The distance of closest approach is approximately twice the radius of iron nucleus.
No, the alpha particle does not touch the iron nucleus.
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Calculate the closest distance a 9 MeV alpha particle can
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If the alpha particles have an initial kinetic energy of 7.7 MeV, then assuming a head-collision between an alpha particle (helium nucleus with +2e charge) and a gold nucleus (79 protons, so +79e charge), and using conservation of energy at the point of closest approach when all of the alpha particle's kinetic energy is converted to electric potential energy, calculate the approximate distance of closest approach (and thus coarsely estimate the size of the nucleus)
An alpha particle with a kinetic energy of 10.0 MeV makes a head-on collision with a...
An alpha particle with a kinetic energy of 10.0 MeV makes a head-on collision with a gold nucleus at rest. What is the distance of closest approach of the two particles? (Assume that the gold nucleus remains stationary and that it may be treated as a point change. The atomic number of gold is 79, and the alpha particle is a helium nucleus consisting of 2 protons and 2 neutrons).
An alpha particle with a kinetic energy of 12.0 MeV makes a head-on collision with a...
An alpha particle with a kinetic energy of 12.0 MeV makes a head-on collision with a gold nucleus at rest. What is the distance of closest approach of the two particles? (Assume that the gold nucleus remains stationary and that it may be treated as a point charge. A gold nucleus has 79 protons, and an alpha particle is a helium nucleus consisting of two protons and two neutrons. The mass of an alpha particle is 6.64424 x 10-27 kg....
An alpha particle with kinetic energy 13.0 MeV makes a collision with lead nucleus, but it...
An alpha particle with kinetic energy 13.0 MeV makes a collision with lead nucleus, but it is not "aimed" at the center of the lead nucleus, and has an initial nonzero angular momentum (with respect to the stationary lead nucleus) of magnitude L=p0b, where p0 is the magnitude of the initial momentum of the alpha particle and b=1.30×10−12 m . (Assume that the lead nucleus remains stationary and that it may be treated as a point charge. The atomic number...
[10] Question 2 The mass of an alpha-particle is 3727 MeV/c2. What is the distance of...
[10] Question 2 The mass of an alpha-particle is 3727 MeV/c2. What is the distance of closet approach for an alpha-particle of kinetic energy 10.0 MeV that backscatters (reverses direction) off a nucleus of uranium (Z-92)? Consider the uranium nucleus to be fixed in space (infinitely massive) and recall that electrostatic potential energy is given by equation: 1h where o 8.854x10-Askg'm
Problem 10.23 An alpha particle (a helium nucleus, containing 2 protons and 2 neutrons) starts out...
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An alpha particle with kinetic energy 11.0 MeV makes a collision with lead nucleus, but it is not "aimed" at the center of the lead nucleus, and has an initial nonzero angular momentum (with respect to the stationary lead nucleus) of magnitude L=p0b, where p0 is the magnitude of the initial momentum of the alpha particle and b=1.50×10−12 m . (Assume that the lead nucleus remains stationary and that it may be treated as a point charge. The atomic number...
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[10] Question 2 The mass of an alpha-particle is 3727 MeV/c2. What is the distance of closet approach for an alpha-particle of kinetic energy 10.0 MeV that backscatters (reverses direction) off a nucleus of uranium (Z-92)? Consider the uranium nucleus to be fixed in space (infinitely massive) and recall that electrostatic potential energy is given by equation: 1h where o 8.854x10-Askg'm
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