Light is gathered from a distant galaxy and one of the spectral lines of Calcium is observed at 413.26 nm when it should be 393.37 nm.
(a) Find the velocity of this galaxy (hint: Doppler formula).
(b) Find the distance to this galaxy (hint: Hubble Law).
Solution:
According to Doppler shift: dw/w = v/c,
where dw is the wavelength shift,
w the nominal wavelength,
v the speed of the object and
c the speed of light.
Here, we have: v/c = dw/w = (413.26 - 393.37) / 393.37 =
0.051
Therefore v= 0.051 x 300,000 km/s = 15,170 km/s [Part-(A)
Ans.]
Now, According to Hubble's law v=H d,
where H = 71 km/s / Mpc
So the galaxy is at a distance of 15,170 / 71 = 214
Mpc
Light is gathered from a distant galaxy and one of the spectral lines of Calcium is...
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