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Calculate the standard entropy variations for the following processes. Do the calculations agree with the predictions?...
help with these please Which of the following transformations represent an increase in the entropy of the system. Choose all that apply 4 mol CO2 (0.727 atm, 498K) 4 mol CO2 (0.727 atm, 249K) 38 g Sb (liquid, 904.0K) 38 g Sb (solid, 904.0K) 46 g C,H,OC Hg (liquid, 172K) 46 g CHOC2Hs (liquid, 293K) 1 mol H2 (8.39 L, 216K) 1 mol H2 (16.8 L, 216K) 46 g C2H5OC2H5 (liquid, 308K) 46 g C2H30C2H5 (gas, 308K) Consider the reaction:...
on 8 wered ked out of Calculate the standard entropy changes for the following processes. Combustion of methane gas in the presence of oxygen to form carbon dioxide and water based on the following equation: CH48) +20218 — CO2/2) +2H2O(g) Flag question Select one: a.-5.2 J/K.mol b. +11.1 J/K.mol C.-11.1 J/K mol d. -5.2 J/K.mol Finis Time
2. How does the entropy of a system change for each of the following processes? Indicate 49<0 or > 0 (a) (b) (c) (d) (e) (f) A solid melts. A liquid freezes. A liquid boils. A vapor is converted to a solid A vapor condenses to a liquid. A solid sublimes. 13. Given that AH value of AG = -2219 kJ/mol and that AS au=-216 JK mol at 25°C, determine the at 25 °C for the reaction CH5g + 50g...
17.51 Calculate the entropy change for the following processes. (a) 1.00 mol H,O(s) melts at 0 °C. AH = 6.01 kJ/mol. (b) 2.00 mol CH.() vaporizes at 80.0 °C. AH vap = 30.7 kJ/mol. 17.52 - Calculate the entropy change for the following processes. (a) 2.00 mol NH3(e) vaporizes at -33.0 °C. AHvap = 23.35 kJ/mol. (b) 1.00 mol C,H,OH(s) melts at -114 °C. AHjus = 5.0 kJ/mol. 17.53 Use data from Appendix G to calculate the standard entropy change...
Which of the following transformations represent an increase in the entropy of the system. Choose all that apply 4 mol Ar (8.44 L, 249K) 4 mol Ar (16.9 L, 249K) 28 g C,H,OH (liquid, 352K) 28 g C,HOH (gas, 352K) 27 g Al (liquid, 933.0K) 27 g Al (solid, 933.0K) 28 g C,H,OH (liquid, 171K) 28 g C,H,OH (liquid, 340K) 3 mol CO2 (0.855 atm, 413K) *3 mol CO2 (0.855 atm, 206K) Submit Answer Retry Entire Group 4 pre group...
Calculate the standard-state entropy for the following reaction: 1 CH4(g) + 2 O2(g) ⟶ 1 CO2(g) + 2 H2O(l) (If applicable, coefficients of one have been included for clarity.) The standard entropy values are given in the table. Formula S∘ J/(K⋅mol) CO2(g) 214 H2O(l) 189 CH4(g) 186 O2(g) 205
1. Out of the following, which system is decreasing in entropy? a. CH,OH,) → CH2OH() C. N2(g) + O2(g) → 2 NOG) b. NaClg) → Nataq) + Clian) d. 2 NO26) ► N20419 2. Which of the following is always spontaneous? a. C2H01) + 302(g) → 2CO2(g) + 3H2O(g) AH<0 b. Sublimation of solid CO2 C. Water freezing d. The formation of water from gaseous hydrogen and oxygen e. None of the above 3. Will liquid water evaporate at room...
Calculate the standard-state entropy for the following reaction: 6 CO2(g) + 6 H2O(l) ⟶ 1 C6H12O6(s) + 6 O2(g) (If applicable, coefficients of one have been included for clarity.) The standard entropy values are given in the table. Formula S∘ J/(K⋅mol) C6H12O6(s) 212 O2(g) 205 CO2(g) 214 H2O(l) 189
Calculate the standard entropy change for the formation of 1.0 mol of the following compounds from the elements at 25 °C. a. C2H2 (g) b. MgCO3 (s) Calculate the standard entropy change for the formation of 1.0 mol of the following compounds from the elements at 25 °C. C2H2(g) a. Use the following data: C2H2(g) C(s, graphite) H2(g) J K·mol 200.94 5.6 130.7 A, Sº = J/Kºmol-rxn MgCO3(s) b. Use the following data: S° MgCO3(s) Mg(s) C(s, graphite) O2(g) K·mol...
1) Identify whether entropy increases, decreases, or remains unchanged during each of the following processes. a) Freezing liquid water b) Dissolving sodium chloride crystals into liquid water c) Expanding argon gas isothermally from 2 bar to 1 bar d) Chilling a steel ball bearing from 100 C to 25 oC e) Crystallizing a protein from an aqueous solution _- f) Heat shrink tubing shrinks (2) For each of the following processes predict qualitatively the sign for the change in entropy...