(1 point) For a group of 80 people, assuming that each person is equally likely to have a birthday on each of 365 days in the year, compute
(a) The expected number of days of the year
that are birthdays of exactly 4 people:
E[days with 4 birthdays]=E[days with 4 birthdays]=
(b) The expected number of distinct
birthdays:
E[distinct birthdays]=E[distinct birthdays]=
a)probability that 4 people have a birthday on a particular day =80C4(1/365)4(364/365)76 =0.0000723
hence expected number of days of the year that are birthdays of exactly 4 people =np=365*0.0000723 =0.0264
b)
P(exactly one birthday on a day)=80C1(1/365)1(364/365)79 =0.1764697
hence E[distinct birthdays]= np=365*0.1764697=64.41144
(1 point) For a group of 80 people, assuming that each person is equally likely to...
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