Professor plays basketball and makes 75% of free throws she shoots. If professor shot 5 free throws today, what is the probability that she makes at least 1?
Solution
Given that ,
p = 0.75
q = 1 - p = 1 - 0.75 = 0.25
n = 5
Using binomial probability formula ,
P(X = x) = (n C x) * p x * (1 - p)n - x
P(X 1 ) = 1 - P( x <1)
= 1 - P(X = 0)
= 1 - (5 C 0) * 0.75 0 * (0.25)5
=1-0.0010
probability=0.9990
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