At 20.0°C, the vapor pressure of ethanol is 45.0 torr, and the vapor pressure of methanol is 92.0 torr. What is the vapor pressure at 20.0°C of a solution prepared by mixing 24.0 g methanol and 80.0 g ethanol?
According to raoult law
Ptotal= XaPa+XbPb
Mole of methanol= 24 g/32g/mol=0.75
Mole of ethanol= 80/46g/mol=1.74
Total mole = 1.74+0.75= 2.49
Mole fraction of methanol= 0.75/2.49=0.301
Mole fraction of ethanol= 1.74/2.49=0.7
Vapour pressure= (0.301*92)+(0.7*45)= 59.2 torr
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