Topic : Rate of Effusion and Molecular Mass PART 1: ANSWERED: 2.198×10-4 mol of an unidentified...

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Topic : Rate of Effusion and Molecular Mass PART 1: ANSWERED: 2.198×10-4 mol of an unidentified...

Topic : Rate of Effusion and Molecular Mass

PART 1: ANSWERED: 2.198×10-4 mol of an unidentified gaseous substance effuses through a tiny hole in 81.4 s. Under identical conditions, 1.840×10-4 mol of argon gas takes 84.4 s to effuse. What is the molar mass of the unidentified substance (in g/mol)?

ans : 26.04 g/mol

PART 2: ANSWERED: The percentage C by mass in the above unidentified substance is 92.3%. It may also contain H and/or O, but no other element. What is the molecular formula of the substance?

ans : C2H2

PART 3 HELP: Under identical conditions, how many moles of cyclobutane (C4H8) gas would effuse in 92.0 s?

science chemistry

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A gas of unknown molecular mass was allowed to effuse through a small opening under constant...

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Topic : Rate of Effusion and Molecular Mass PART 1: ANSWERED: 2.198×10-4 mol of an unidentified...

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A gas of unknown molecular mass was allowed to effuse through a small opening under constant...

#11-12 milk and Ar 4. A 010 (part 1 of 3) 10.0 points The molecular mass of helium is 4 g/mol, the Boltzmann's constant is 1.38066× How 10-23 J/K, the universal gas constant is ice c 8.31451...

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Topic : Rate of Effusion and Molecular Mass PART 1: ANSWERED: 2.198×10-4 mol of an unidentified...