What current (in A) flows through the bulb of a 3.20 V flashlight when its hot resistance is 3.75 Ω?
Answer
Resistance of th bulb (R) = 3.75 ohm's
Voltage across the bulb (V) = 3.20 Volts
Therefore the current flowing through the bulb
I = V/R
= 3.20/(3.75)
= 0.8533333333 Amps
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