(USING THE PROGRAM MARS) Using the MemoryAccess program we wrote in class as a starting point, write a program called LoadStore
# Title : Memory access.asm
#Desc: Practice initially memory,
#in val1 = 0x0a;
#int val2 = 0x0b;
#int result;
#string resultstring = " final answer : ";
#string returnchar = "\n";
#void main() {
# result = val1 + val2;
# cout<<< resultstring <<
returnchar;
#}
.data
val1: .word 0x0a #store 0xa into variable val1
val2: .word 0x0b #store 0xb into val2
result: .word 0 #destination
resultstring: .asciiz "final answer is: "
returnchar: .asciiz "\n"
.text
.globl main
main:
#load our values into
registers
lw $t0, val1
lw $t1, val2
#do the math
add $t0, $t0, $t1
#store the total back into
result
sw $t0, result
#series of 3 prints. string then
number then string
li $v0, 4 #syscode for
printing a string
la $a0, resultstring
#address of string to print
syscall
#print an integer
li $v0, 1 #syscode for
printing an int
lw $a0, result #we
want the value in $a0
syscall
#print return charater
li $v0, 4
la $a0, returnchar
syscall
#get out of dodge
li $v0, 10
syscall
^^^^^^^^^^^^^^^^^^memory access program
The Algorithm for your program is as follows:
Your output should look as follows (Example User Input is shown in bold):
Please enter the first
number: 12
Please enter the second
number: 13
Please enter the third number: 14
Result: 12 + 13 – 14 = 11
---------------------------------------
Hint: The operators are strings
PROGRAM:
.data
val1: .space 4
val2: .space 4
val3: .space 4
result: .space 4
prompt1: .asciiz "Please enter first number: "
prompt2: .asciiz "Please enter second number: "
prompt3: .asciiz "Please enter third number: "
output: .asciiz "Result: "
plus: .asciiz " + "
minus: .asciiz " - "
equal_sign: .asciiz " = "
.text
.globl main
main:
li $v0,4
# 4 is the print string syscall
la $a0,prompt1
# Address of the string to be printed
syscall
# Print the string
li $v0,5
# 5 is the read integer syscall
syscall
# Read the integer
sw $v0,val1
# Store the integer in val1
li $v0,4
# 4 is the print string syscall
la $a0,prompt2
# Address of the string to be printed
syscall
# Print the string
li $v0,5
# 5 is the read integer syscall
syscall
# Read the integer
sw $v0,val2
# Store the integer in val2
li $v0,4
# 4 is the print string syscall
la $a0,prompt3
# Address of the string to be printed
syscall
# Print the string
li $v0,5
# 5 is the read integer syscall
syscall
# Read the integer
sw $v0,val3
# Store the integer in val3
lw $s0,val1
# Load val1 into $s0
lw $s1,val2
# Load val2 into $s1
lw $s2,val3
# Load val3 into $s2
add $s3,$s0,$s1
# $s3 = $s0 + $s1
sub $s3,$s3,$s2
# $s3 = $s3 - $s2
sw $s3,result
# Store $s3 into memory
li $v0,4
# 4 is the print string syscall
la $a0,output
# Address of the string to be printed
syscall
# Print the string
li $v0,1
# 1 is the print integer syscall
lw $a0,val1
# Load integer to be printed
syscall
# Print the integer
li $v0,4
# 4 is the print string syscall
la $a0,plus
# Address of the string to be printed
syscall
# print the string
li $v0,1
# 1 is the print integer syscall
lw $a0,val2
# Load integer to be printed
syscall
# Print the integer
li $v0,4
# 4 is the print string syscall
la $a0,minus
# Address of the string to be printed
syscall
# Print the string
li $v0,1
# 1 is the print integer syscall
lw $a0,val3
# Load integer to be printed
syscall
# Print the integer
li $v0,4
# 4 is the print string syscall
la $a0,equal_sign #
Address of the string to be printed
syscall
# Print the string
li $v0,1
# 1 is the print integer syscall
lw $a0,result
# Load integer to be printed
syscall
# Print the integer
li $v0,10
# 10 is exit program syscall
syscall
# Exit the program
Please refer to the following screenshot of the program for indentation of the code:
OUTPUT:
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