From the end of a string (whose other end is firmly attached to the ceiling) we...

Question

Question

From the end of a string (whose other end is firmly attached to the ceiling) we attach a mass m₁. Similarly, we attach a mass m₂ from the end of a different string. Both strings have equal lengths and the masses are barely in contact when they are hanging freely. We pull out both masses so that they form angles θ₁ and θ₂, respectively, with their equilibrium (vertical) positions. We then release the masses at the same time so that there is an elastic, heads-on collision when they reach their equilibrium (vertical) positions. If, after this collision, the masses return to their initial positions given by those angles θ₁ and θ₂, find the ratio of the two masses, m1/m2. (Answer: m₁/m₂ = sqrt((1-cosθ₂)/(1-cosθ₁)))

Answer 1

Answer #1

Answer 2

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