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A single loop of aluminum wire, lying flat in a plane, has an area of 7.80...

A single loop of aluminum wire, lying flat in a plane, has an area of 7.80 cm2 and a resistance of 2.70 Ω. A uniform magnetic field points perpendicular to the plane of the loop. The field initially has a magnitude of 0.500 T, and the magnitude increases linearly to 3.00 T in a time of 1.08 s. What is the induced current (in mA) in the loop of wire over this time?

......................mA

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Answer #1

induced current = induced emf / Resistance

i = A (dB/dt) / R

i = 7.8* 10^-4* ( (3 - 0.5) / 1.08) / 2.7

i = 0.6687 mA

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