Question

python

Define a function called print_values which takes a dictionary object as a parameter. The function should print all values in the dictionary. However, the order is based on the sorted keys in the dictionary. For example, if we have the following dictionary:

{'b':36, 'a':12, 'c':24}

The output is:

12 36 24 

A faulty solution has been provided below. Identify the fault and submit a corrected version of this code.

def print_values(dict1):
    for k in list(dict1.keys()).sort(): 
        print(dict1[k], end=" ")

For example:

Test	Result
print_values({'b':36, 'a':12, 'c':24})	12 36 24
print_values({97:'a', 65:'A', 43:'+', 48:'0'})	+ 0 A a

Answer 1

def print_values(dict1):
        for k in sorted(list(dict1.keys())): 
                print(dict1[k], end=" ")
        print()
        
print_values({'b':36, 'a':12, 'c':24})
print_values({97:'a', 65:'A', 43:'+', 48:'0'})

The sort method sorts the given list in place and returns None.. Hence the for loop fails.. you should use sorted method, which returns the sorted list, on which for loop can work.

please upvote. Thanks!