At a given temperature, 2.06 atm of H2 and 3.7 atm of Br2 are mixed and...
At a given temperature, 2.06 atm of H2 and 3.7 atm of Br2 are mixed and allowed to come to equilibrium. The equilibrium pressure of HBr is found to be 1.345 atm. Calculate Kp for the reaction at this temperature. H2(g) + Br2(g) <=> 2 HBr(g). Use 3 decimal places.
Homework Answers
Add Answer to:
At a given temperature, 2.06 atm of H2 and 3.7 atm of Br2 are
mixed and...
5. A mixture of H2 gas (PH2 2.05 atm), CO2 gas (Pco2 4.10 atm) and water...
5. A mixture of H2 gas (PH2 2.05 atm), CO2 gas (Pco2 4.10 atm) and water vapor (PH20-3.28 atm) are allowed to come to equilibriurm in a closed container. The temperature is 500. K. The equilibrium represented by the equation below is established and the equilibrium partial pressure of H20 is determined to be 3.51 atm. a) Find the equilibrium partial pressures of the CO2, H2, and CO gases. CO2 (g) H2 (g) ←→ CO (g) H2O (g) + +...
The equilibrium constant for the following reaction: H2(g) + Br2(g) ↔ 2HBr (g) is 1.20 x...
The equilibrium constant for the following reaction: H2(g) + Br2(g) ↔ 2HBr (g) is 1.20 x 103 at a certain temperature. Find the equilibrium pressure of HBr if 9.20 atm of HBr is introduced into a sealed container at this temperature.
The equilibrium constant for the following reaction: H2(g) + Br2(g) ↔ 2HBr (g) is 1.35 x...
The equilibrium constant for the following reaction: H2(g) + Br2(g) ↔ 2HBr (g) is 1.35 x 103 at a certain temperature. Find the equilibrium pressure of HBr if 5.70 atm of HBr is introduced into a sealed container at this temperature.
The equilibrium constant for the following reaction: H2(g) + Br2(g) ↔ 2HBr (g) is 1.90 x...
The equilibrium constant for the following reaction: H2(g) + Br2(g) ↔ 2HBr (g) is 1.90 x 103 at a certain temperature. Find the equilibrium pressure of HBr if 14.50 atm of HBr is introduced into a sealed container at this temperature.
For the following reaction, Kp = 2.8 ✕ 104 at 1630 K. H2(g) + Br2(g) equilibrium...
For the following reaction, Kp = 2.8 ✕ 104 at 1630 K. H2(g) + Br2(g) equilibrium reaction arrow 2 HBr(g) What is the value of Kp for the following reactions at 1630 K? (a) HBr(g) equilibrium reaction arrow 1/2 H2(g) + 1/2 Br2(g) (b) 2HBr(g) equilibrium reaction arrow H2(g) + Br2(g) (c) 1/2H2(g) + 1/2 Br2(g) equilibrium reaction arrow HBr(g)
1. At a given temperature the Kp = 4.76x10-4 for the reaction: H2(g) + 12(g) =...
1. At a given temperature the Kp = 4.76x10-4 for the reaction: H2(g) + 12(g) = 2 HI(g) Calculate the equilibrium partial pressure of Hl if the original reaction mixture contains H2 gas at 0.752 atm, 12 gas at 0.752 atm and Hl gas at 0.134 atm. a) 0.321 atm b) 0.810 atm c) 0.0177 atm d) 0.015 atm e) 0.192 atm
2-Consider the reaction H2(g) + Br2(g)  
2-Consider the reaction H2(g) + Br2(g) 2 HBr (g⇌ ) where ΔHo = -36.4 kJ/mol. In one experiment, equal amounts in moles of H2(g) and Br2(g) were mixed in a 2.00 L chamber at 25 oC exerting a pressure P = 1.0 atm. After mixture reached equilibrium, partial pressure of H2 gas PH2 was measured using high sensitivity HVAC gauge recording, PH2 = 5x10-4 Pa. For this equilibrium reaction, answer the following: (i)Calculate the total amount nT of gases...
Given the reaction at a certain temperature: H2(g) + I2(g) ↔ 2 HI(g). At equilibrium, the...
Given the reaction at a certain temperature: H2(g) + I2(g) ↔ 2 HI(g). At equilibrium, the partial pressure of HI is 3.8×10–3 atm and the partial pressures of H2 and I2 are 0.20 atm each. The Kp of this reaction is [X]. (Fill in the blank; report with correct number of significant figures.
35) Given the equilibrium reaction at constant pressure: 2HBr(g) + 72.7 kJ = H2(g) + Br2(g)...
35) Given the equilibrium reaction at constant pressure: 2HBr(g) + 72.7 kJ = H2(g) + Br2(g) When the temperature is increased, the equilibrium will shift to the A) left, and the concentration of HBr(g) will decrease B) right, and the concentration of HBr(g) will decrease C) right, and the concentration of HBr(g) will increase D) left, and the concentration of HBr(g) will increase
The value of the equilibrium constant for the reaction 2HBr(g)<....>H2(g)+Br2(g) is Kc=1.26*10^-12 at 500k. A. what...
The value of the equilibrium constant for the reaction 2HBr(g)<....>H2(g)+Br2(g) is Kc=1.26*10^-12 at 500k. A. what would be the value of the equilibrium constant K'c for the related reaction written in the following fashion? 1/2 H2(g)+1/2 Br2(g)<....>HBr(g). B. what will be the corresponding value for Kp, the pressure form of the equilibrium constant? (R=0.08206)
5. A mixture of H2 gas (PH2 2.05 atm), CO2 gas (Pco2 4.10 atm) and water vapor (PH20-3.28 atm) are allowed to come to equilibriurm in a closed container. The temperature is 500. K. The equilibrium represented by the equation below is established and the equilibrium partial pressure of H20 is determined to be 3.51 atm. a) Find the equilibrium partial pressures of the CO2, H2, and CO gases. CO2 (g) H2 (g) ←→ CO (g) H2O (g) + +...
1. At a given temperature the Kp = 4.76x10-4 for the reaction: H2(g) + 12(g) = 2 HI(g) Calculate the equilibrium partial pressure of Hl if the original reaction mixture contains H2 gas at 0.752 atm, 12 gas at 0.752 atm and Hl gas at 0.134 atm. a) 0.321 atm b) 0.810 atm c) 0.0177 atm d) 0.015 atm e) 0.192 atm
35) Given the equilibrium reaction at constant pressure: 2HBr(g) + 72.7 kJ = H2(g) + Br2(g) When the temperature is increased, the equilibrium will shift to the A) left, and the concentration of HBr(g) will decrease B) right, and the concentration of HBr(g) will decrease C) right, and the concentration of HBr(g) will increase D) left, and the concentration of HBr(g) will increase
Most questions answered within 3 hours.
-
bacteria and their metabolites could either promote or protect from
cancer. Explain one of these cases...
asked 3 minutes ago -
Use the sample data and confidence level given below to complete
parts (a) through (d).
A...
asked 46 minutes ago -
During laser vision correction, a brief burst of 193 nm
ultraviolet light is projected onto the...
asked 44 minutes ago -
1 ) How well does the initial speed, v0,calculated from Equation
4 agree with the value...
asked 46 minutes ago -
1. What is the p-value for a right tail test for a single
proportion with a...
asked 2 hours ago -
A technician compares repair costs for two types of microwave
ovens (type I and type II)....
asked 1 hour ago -
A certain statistical test is designed so that it fails 2% of
the time. Suppose that...
asked 1 hour ago -
For the reaction: H2S(g) + 2H2O(l)3H2(g) + SO2(g) H° = 295 kJ
and S° = 295...
asked 2 hours ago -
The first-order reaction C4H8→2C2H4 has the reaction constant k
of 7.60×10−3 s−1. If the initial concentration...
asked 1 hour ago -
46.3 mL of a 0.0999 M solution of this acid (HOOC-(CH2)2-COOH)
is titrated to the equivalence...
asked 1 hour ago -
What is the difference between steady-state and equilibrium? Be
sure to include three properties of each...
asked 1 hour ago -
1..Research the microorganisms listed below. List the full
taxonomy (phylum, class, order, family, genus, species) of...
asked 1 hour ago