What is the component concentration ratio, [BrO−]/[HBrO], of a buffer that has a pH of 8.02?
(Ka of HBrO = 2.3 × 10−9)
Sol.
As Ka of HBrO = 2.3 × 10-9
So , pKa = - log(Ka) = - log ( 2.3 × 10-9 ) = 8.64
Using Henderson - Hasselbalch Equation ,
pH = pKa + log ( [BrO-] / [HBrO] )
8.02 = 8.64 + log ( [BrO-] / [HBrO] )
log ( [BrO-] / [HBrO] ) = 8.02 - 8.64 = - 0.62
[BrO-] / [HBrO] = 10-0.62 = 0.2399
What is the component concentration ratio, [BrO−]/[HBrO], of a buffer that has a pH of 8.02?...
What is the component concentration ratio, [BrO−]/[HBrO], of a buffer that has a pH of 8.07? (Ka of HBrO = 2.3 × 10−9)
Calculate the ratio of the molar concentrations of BrO- and HBrO required to achieve buffering at pH = 7.95. For HBrO, Ka = 2.3 × 10-9. [base]/[acid] = 4.9 [base]/[acid] = 3.16 [base]/[acid] = 0.50 [base]/[acid] = 0.61 [base]/[acid] = 0.20
What is the component concentration ratio, [Pr−]/[HPr], of a buffer that has a pH of 4.53? (Ka of HPr = 1.3 × 10−5)
What is the component concentration ratio, [Pr−]/[HPr], of a buffer that has a pH of 4.57? (Ka of HPr = 1.3 × 10−5) Report your answer to 3 significant figures.
What is the buffer component ratio, (NO2-)/(HNO2) of a nitrite buffer that has a pH of 2.96. Ka of HNO2 is 7.1 x 10-4.
Calculate the pH of a buffer solution that is composed of 0.200 M HBrO and 0.348 M NaBrO. Ka for HBrO is 2.3 x 10-9. Enter a numerical value in the correct number of significant figures.
QUESTION 6 What is the buffer component ratio, (CH3CH2COO(CH3CH2COOH) of a propanoate buffer that has a pH of 4.77. Ka of CH3CH2COOH is 1.3 x 10-5. Enter your answer with three decimal places and no units.
What is the pH of a buffer made from 0.350 mol of HBrO (Ka = 2.5 × 10⁻⁹) and 0.160 mol of KBrO in 2.0 L of solution?
Which of the following acids should be used to prepare a buffer with a pH of 5.9? HOCH2COOH, Ka = 3.5 × 10–4 HClO2, Ka = 1.1 × 10–2 HBrO, Ka = 2.3 × 10–9 ClCH2COOH, Ka = 1.4 × 10–3 C6H13NO4S, Ka = 7.08 x 10-7
Which is the best choice for preparing a buffer with a pH of 3.5? CsH505COOH, K, - 4.0 x 10-6 HOCgH4OCOOH. Ka 1.0x 10-3 HBRO, Kg = 2.3 x 10-9 CeHa(COOH)2. Ka = 2.9x 104 CH3COOH, Ka 1.8 10-5