The mass of a star is 1.53·1031 kg and its angular velocity is 1.50E-7 rad/s. Find its new angular velocity if the diameter suddenly shrinks to 0.27 times its present size. Assume a uniform mass distribution before and after. Icm for a solid sphere of uniform density is 2/5 mr2.
The mass of a star is 1.53·1031 kg and its angular velocity is 1.50E-7 rad/s. Find...
star The mass of a star is 1.630×1031 kg and it performs one rotation in 28.30 days. Find its new period (in days) if the diameter suddenly shrinks to 0.590 times its present size. Assume a uniform mass distribution before and after.
The mass of a star is 1.770×1031 kg and it performs one rotation in 21.90 days. Find its new period (in days) if the diameter suddenly shrinks to 0.590 times its present size. Assume a uniform mass distribution before and after. A figure skater is spinning with an initial angular speed of 9.8rad/s. He then pulls his arms in, reducing his moment of inertia to 0.27 times its original value. What is his angular speed after pulling in his arms?...
1, A star with a mass of 1.25 × 1031 kg and a radius of 3.45 × 105 km is initially rotating on its axis with a period of 24.0 days. The star collapses and becomes a neutron star with a radius of 12.5 km, retaining all of its original mass. Assume the star is a uniform solid sphere before and after the collapse, with a moment of inertia given by (2/5)MR2. What is the period of rotation after collapse?...
The mass of a star is 1.030x1031 kg and it performs one rotation in 38.50 days. Find its new period (in days) if the diameter suddenly shrinks to 0.730 times its present size. Assume a uniform mass distribution before and after. Submit Answer Tries 0/12
A disk with radius 0.6 meters and mass 31 kg is spinning about its own center with an angular velocity of 88ed A solid sphere (/ mR2) with a radius of 0.18 meters which is spinning with an angular velocity of -18 ed (the negative sign indicates the opposite 6. rad sec direction), is gently lowered onto the disk a sticks to the disk. The two rotate together (about their mutual center of mass) at an angular velocity of 33...
5*) Find the angular velocity of the Earth due to its daily
rotation and express it in radians per second. Then use it, and a
model of the Earth as a solid sphere of mass M=
5.97 × 1024 kg and radius R
= 6.37 × 106 m, to estimate the angular momentum of the Earth due
to its rotation around its axis. (The result should be of the order
of 1033 kg m2/s. This is called the Earth’s “intrinsic”...
A 3.9-m-diameter merry-go-round is rotating freely with an angular velocity of 0.80 rad/s . Its total moment of inertia is 1350 kg⋅m2 . Four people standing on the ground, each of mass 68 kg , suddenly step onto the edge of the merry-go-round. What is the angular velocity of the merry-go-round now?
10*) The Sun has approximate radius 7×108 m, and rotates around
its axis once every 27 days. a) Find its angular velocity in rad/s,
and (assuming it is a uniform sphere) write a formula for its
angular momentum expressing it in terms of its mass M (you do not
need to substitute a value for M). b) Suppose the Sun were to
collapse to a neutron star, which is a much denser state, without
losing any mass and without being...
A 4.5-m-diameter merry-go-round is rotating freely with an angular velocity of 0.84 rad/s . Its total moment of inertia is 1700 kg⋅m2 . Four people standing on the ground, each of mass 68 kg , suddenly step onto the edge of the merry-go-round. What is the angular velocity of the merry-go-round now? What if the people were on it initially and then jumped off in a radial direction (relative to the merry-go-round)?
A solid disk rotates in the horizontal plane at an angular velocity of 0.0612 rad/s with respect to an axis perpendicular to the disk at its center. The moment of inertia of the disk is 0.134 kg·m2. From above, sand is dropped straight down onto this rotating disk, so that a thin uniform ring of sand is formed at a distance of 0.398 m from the axis. The sand in the ring has a mass of 0.509 kg. After all...