Balance the following half-reactions in acidic solution, identify the oxidation states of the metal atoms, and use the predominance diagrams to determine the standard reduction potentials.
ReO4 - → ReO3
HSeO4 - → H2SeO3
a)ReO4 -ReO3
In ReO4, Re is in +7 oxidation state
In ReO3, Re is in +6 oxidation state
This is reduction half cell
Balence oxygen with water
ReO4 -ReO3 + H2O
Balence hydrogen with H+
ReO4 - + 2H+
ReO3 + H2O
Balence electron
ReO4 - + 2H+ +1e-
ReO3 + H2O (1)
(b)HSeO4 -H2SeO3
HSeO4 -, Se in +6 oxidtion state
H2SeO3, Se in +4 oidation state
reduction
SeO4 2-SeO32-
SeO4 2-SeO32- + H2O
2H+ + SeO4 2-SeO32- + H2O
2H+ + 2e- + SeO4 2-SeO32- + H2O (2)
Hence balenced equation
a)ReO4 -ReO3
In ReO4, Re is in +7 oxidation state
In ReO3, Re is in +6 oxidation state
This is reduction half cell
Balence oxygen with water
ReO4 -ReO3 + H2O
Balence hydrogen with H+
ReO4 - + 2H+
ReO3 + H2O
Balence electron
ReO4 - + 2H+ +1e-
ReO3 + H2O (1)
(b)HSeO4 -H2SeO3
HSeO4 -, Se in +6 oxidtion state
H2SeO3, Se in +4 oidation state
reduction
SeO4 2-SeO32-
SeO4 2-SeO32- + H2O
2H+ + SeO4 2-SeO32- + H2O
2H+ + 2e- + SeO4 2-SeO32- + H2O (2)
Hence balenced equation
Balance the following half-reactions in acidic solution, identify the oxidation states of the metal atoms, and...
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