If X has a normal distribution with mean µ = 12 and variance σ2 = 9, compute P (12 < X < 15).
A |
0.3413 |
|
B |
0.9651 |
|
C |
0.8413 |
|
D |
0.5000 |
Solution :
Given that ,
mean =
= 12
standard deviation =
= 3
P(12 < x < 15) = P[()12 - 12/ 3) < (x -
) /
<
(15 - 12) / 3) ]
= P(0 < z < 1)
= P(z < 1) - P(z < 0)
= 0.8413 - 0.5
= 0.3413
P(12 < x < 15) = 0.3413
option A is correct
If X has a normal distribution with mean µ = 12 and variance σ2 = 9,...
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