Chemistry

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Chemistry

The "roasting" of 48.7 g of ZnS at constant pressure gives off 220. kJ of heat. Calculate the DH for this reaction.

2ZnS(s) + 3O2(g) ® 2ZnO(s) + 2SO2(g)

A.) -110 kJ/mol rxn

B.) -293 kJ/mol rxn

C.) -440. kJ/mol rxn

D.) -881 kJ/mol rxn

E.) +440. kJ/mol rxn

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Answer 1

Answer #1

D.) -881 kJ/mol rxn

answered by: lissette

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Answer 2

Answer #2

B is correct

answered by: Renea

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Answer 3

Answer #3

48.7 g implies =48.7/97.47 mole
= .5 moles
.5 moles produces 220 kg
Dh of reaction is 2*440= 880kj
option d

answered by: sabrine

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Answer 4

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