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A light ray leaves point A in the figure, reflects from the mirror, and reaches point B.

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A light ray leaves point A in Figure 1, reflects from the mirror, and reaches point B. How far below the top edge does the ray strike the mirror? What if the distance from point B to the mirror was reduced by 5 cm?

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Answer #2

As angle of incident-angle ofreflection-o Completing the triangle AOC and BOD In triangle AOC tano AC/OC-x In triangle BOD ta

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The incident and reflected light rays will form two right angled triangles as shownFrom the laws of reflection,the angle of incidence = the angle of reflectionx / 10 cm = (10 cm - x) / 15 cm15 x = 100 - 10x25x = 100x = 4 cmTherefore the light ray will strike the mirror at 9 cm below the top edge
answered by: Tania
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