Question

an adult 68 kg cheetah can accelerate from rest to 20.1 m/s (45 mph) in 2.0 s. Assuming constant acceleration, (a) find the net external force causing this acceleration. (b) where does the force come from? that is, what exerts the force on the cheetah?

Answer 1

should i be using the equation you wrote for finding the net EXTERNAL force??

Answer 2

Yes. That is the force accelerating the cheeta.

Answer 3

i corrected it and i got 683.4 N, does that sounds right? if yes, would it be 6.8E-1?

Answer 4

i don't get the first equation explain more please

Answer 5

a= deltav/time

F=ma

Doesn't the ground exert force on the cheta?

Answer 6

i got 1366.8 N and i'm asked to round to SF would it be 1.3*10^2?

Answer 7

a= 20.1m/s /2= 10.05m/s^2
F= ma

How did you get that number 1366?

Now, rounding 1366.8 is not 1/3E2

E2 is 100. But you have other errors that need to be corrected.

Answer 8

acceleration= changeinvelocity/time.

Answer 9

(20.1 m/s) divide by 2.0 s = 10.05

10.05 (68.0)= 683.4