Question

Hydrostatic Force on a Plane Surface

Two square gates close two openings in a conduit connected to an open tank of water as shown in Fig. P2.34. When the water depth, h, reaches 5 m it is desired thatboth gates open at the same time. Determine the weight of the homogeneous horizontal gate and the horizontal force, R, acting on the vertical gate that is requiredto keep the gates closed until this depth is reached. The weight of the vertical gate is negligible, and both gates are hinged at one end as shown. Friction in thehinges is negligible.

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Answer #1
Consider the torque around the hinge in horizontal gate
T(weight)=2W (weight acts in the centre of the plate)
Pressure due to water at the gate=pg(5-3)
This force also acts in the centre of the gate.
2W=1000*10*2*16*2
W=320000 N

For vertical gate
T net due to pressure around the hinge =integral of (pgh*4*(9-h)) from 5 to 9.
T net=2026666.66
R*4 =2026666.66
R=506666.66 N
answered by: Benjamin
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