two impedances z1=3+j6 ohms and z2=4-j3 ohms are connected in series
Given: Z1 = 4-j1.5 ohms; Z2 = 2+j4 ohms; Z3 = 2 ohms; 24 = 3 + j5 ohms. If the four impedances are connected in parallel, find the magnitude of equivalent impedance in ohms. (No need to include the phase angle, ONLY THE MAGNITUDE)
Q2. A three-phase unbalanced delta-connected load containing impedances Z1, Z2 and resistor R3 is connected to a three-phase power source of 380 V, 50 Hz in positive sequence A-B-C as shown in figure Q2. It is known that line current Ic is 54 292° A. The power consumption of load R3 is 18050 W. The impedance of Zi is 20 -70° 2. By taking VAB as reference, calculate B BB/ Z2 TBC figure Q2 (a) the line voltage VAB, VBC...
if the two branches of a 440v parallel circuit have the impedences z1=2-j and z2 1+j3 what is the true power in the circuit
Let Z! = 3H4, Z2-5-2, Z,--3-12, Z4--10-j6, and Z5--6-3. 1. Calculate Z1 + Z2 in rectangular form. 2. Calculate Z1 - Z2 in rectangular form. 3. Calculate Z3 + Z4 in polar form. 4. Calculate Za - Z5 in polar form. 5. Calculate Z1Z2-Z3 in rectangular form. 6. Find ZsZ7 in polar form. 7. Find Z7Zs in rectangular form. 8. Find ZsZs+Z7 in rectangular form Reduce the following to rectangular form. 10. Z1/Z2
Using complex or magnitude angle math to solve for Z, V or I Let Z1 = (2 + j2) Zg = (1 + j2) Zg = (4 + j2) 11 = (4 + j2) Solve for A) Zi + Za + Zs (Series impedances) B) Zi ll Z2三? (Parallel impedances) C) Il * Z3-) (Ohms Law) D) Vı/Zs-? (Ohms Law)
A balanced delta connected 3 phase load with per phase impedance
of
Z1 = 3 + j9 (Ohm)
is connected in parallel to a balanced 3 phase star connected load
with per phase impedance:
Z2 = 6 + j16 (Ohm).
Their connection is shown in the Picture attached. This load
combination is connected to a balanced 3 phase 415V (line-to-line)
supply.
Find the magnitude of the line current drawn from the supply. Enter
your results in Amps with one digit...
) are connected in a wye configuration. 4.. • • 3 impedances (Z = 8 + j6 Line voltage is 480v. Calculate: Phase current = Line current = 11 11 11 11
A network operates at f=50 Hz that has different loads connected in series and this network has a current of 10 Arms. The two loads in the system are: Z1=30 angle 15 degrees Ohms and Z2=40 angle 40 ohms. a) What is the Power Factor operating the source? b) What is the value of the capacitor that must be connected in the series circuit to provoke a PF of 0.9 lagging?
In a balanced three-phase system, the source is wye-connected and the source voltage of phase A is Van = ∠ 120 20 V. The load consists of two balanced wyes in parallel with phase impedances of 8 + j6 Ω and 12 + j8 Ω. If the line impedance is zero, find the line currents and the phase currents in each load. (Hint: use per phase analysis, then do angle shift for each phase.)
4. (20 points) The three-phase Y-connected power supply has a line-to-neutral voltage KIN of 1.220° KV. A balanced-A load consisting of impedance Z1-20 30 Ω per phase is in parallel with a balanced-Y load having phase impedance of Z2 = 15245° Ω. Identical line impedances of Z1 = 3L15。Ω are in each of the three lines connecting the combined loads to the phase supply (a) Draw the per-phase equivalent circuit; (b) Find the line-to-line voltage Vab (magnitude and angle) at...