F(s)= 1 /s(s^2+4s+5)
F(s)= 1 /s(s^2+4s+4+1)
F(s)= 1 /s((s+2)^2+1)
F(s)= (1 /s) * (1/((s+2)^2+1)
we know that L (u(t) = 1/s L(e^-2t sint u(t)) = (1/((s+2)^2+1)
thus
inverse laplace transform given by = u(t)*e^-2t sint u(t)
apply the convolution theorem to find the inverse laplace transform of ;
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