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FINDING A POINT ON THE SURFACE GIVEN AN EQUATION....

FIND THE POINT ON THE SURFACEZ = 3X2 - Y2 AT WHICH THE TANGENT PLANE IS PARALLEL TO THE PLANE 6X +4Y - Z = 5

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Answer #1

The plane 6x + 4y - z = 5 has normal (6, 4, -1).

The normal to the surface 3x2 - y2 - z = 0 is (6x, -2y, -1) (The gradient!) Setting (6x, -2y, -1) = (6, 4, -1) we seethat x = 1, y = -2.

Remark: The normal to the level set of a function is given by the gradient, so rewriting the original surface as the zero level set of thefunction F(x, y, z) = 3x2 - y2 - z allows us to easily find the normal, and parallel planes in 3-d have the same normals.

answered by: Lenora
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