FIND THE POINT ON THE SURFACEZ = 3X2 - Y2 AT WHICH THE TANGENT PLANE IS PARALLEL TO THE PLANE 6X +4Y - Z = 5
The plane 6x + 4y - z = 5 has normal (6, 4, -1).
The normal to the surface 3x2 - y2 - z = 0 is (6x, -2y, -1) (The gradient!) Setting (6x, -2y, -1) = (6, 4, -1) we seethat x = 1, y = -2.
Remark: The normal to the level set of a function is given by the gradient, so rewriting the original surface as the zero level set of thefunction F(x, y, z) = 3x2 - y2 - z allows us to easily find the normal, and parallel planes in 3-d have the same normals.
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The equation of a surface is f(x, y) = 4xy + x2 - y2 +9. Which is an equation of the plane that is tangent to the surface at the point(4,2,49)? 34x –19y –20 b) z =-18x-12y +20 c) z = 5x-3y +27 d)z=16x+4y-23 e) z =-12x-18y+20
Exercise 1. Tangent plane (15 pts) Let (5) be the surface given by the following equation. x2+y2 = 1+z2 An equation of the tangent plane to (S) at A(1,2,2) is: a. 2x + 4y – 4z = 1 b. x + y - z=0 c. x + 2y – 2z = 1 d. x + y - z = 2 e. None of the above a. b. C. O d. e. Exercise 2. Directional derivative (6 pts + 9 pts)...
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1 point) Find the surface area of the part of the sphere x2 + y2 + z2-1 that lies above the cone z = x2+y2 Surface Area
(1 point) Find...