A 32.5g cube of aluminum initially at 45.8 C is submerged into 105.3g water at 15.4 C
A 32.5 g cube of aluminum initially at 45.8 oC is submerged into 105.3 g of water at 15.4 oC. What is the final temperature of both substances at thermal equilibrium? The specific heat of Al is 0.903 J/g • oC. The specific heat of water is 4.184 J/g • oC. (Hint: your answer should not contain any units and have three significant figures)
this is the answer but i dont get why they put (45.8-Tf) instead of (Tf-45.8). shouldnt the format be (Tf-Ti)? like for the eqution on the other side of the = sign its (Tf-15.4) and its in the format of (Tf-Ti). help A 32.5 g cube of aluminum initially at 45.8 Celsius is submerged into 105.3g of water at 15.4 Celsius. What is the final temperture of both substances at thermal equilibrium Best Answer Sharlene J answered this lets tf...
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A 6.66 g lead weight, initially at 9.3 oC, is submerged in 10.00 g of water at 52.3 oC in an insulated container. What is the final temperature of both substances at thermal equilibrium? Specific heat capacity of lead = 0.128 J/gC; water = 4.18 J/gC O A. 52.3 oC OB. 51.4 OC OC. 53.6 oC OD. 49.4 oC OE. 50.3 oC OF. 47.6 OC O G. 48.4 oC OH. None of the above