Question

physics - acceleration

To withstand "g-forces" of up to 10 g's, caused by suddenly pulling out of a steep dive, fighter jet pilots train on a "human centrifuge". 10 g's is an acceleration of98 m/s^2.

If the length of the centrifuge arm is 12.0 m, at what speed is the rider moving when she experiences 10 g's? Express answer with the appropriate units.
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Answer #1
a = v^2 / r

so v = root(a/r) = root(98/15) = 2.55 ms^-1
hope will b hlpfull
answered by: rodrigo
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Answer #2

a = (v^2)/r

or 

v = squareroot(a x r)


v = squareroot(98 x 12)

v = 34.29

answered by: saracia23
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