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Electric Potential

Suppose a diode consists of a cylindrical cathode with a radius of 6.200×10-2 cm, mounted coaxially within a cylindrical anode with a radius of 0.5580 cm. Thepotential difference between the anode and cathode is 235 V. An electron leaves the surface of the cathode with zero initial speed (v_{rm initial} = 0). Find itsspeed v_final when it strikes the anode.
Express your answer numerically in meters per second.
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Answer #1
Letv = Velocity of electron at anodeV = Potential difference = 235 Vm = Mass of the electronKinetic energy at anode = Potential energy at cathode(1/2) m v^2 = q Vv = √ ( 2 q V / m )= √ [ ( 2 * 1.6 x 10^-19 * 235 ) / ( 9.1 x 10^-31 ) ]= 9.1 x 10^6 m/s
answered by: jolomi
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