A normal distribution has a mean of 80 and a standard deviation of 14
A normal distribution has a mean of 60 and a standard deviation of 10. Refer to the table in Appendix B.1. Determine the value above which 80 percent of the values will occur. (Round z-score computation to 2 decimal places and the final answer to 2 decimal places.) X
A normal distribution has a mean of 25 and a standard deviation of 3. Find the value above which there is a .70 probability that an observation will occur. (4 points)
A normal distribution has a mean of 25 and a standard deviation of 3. Find the value above which there is a .70 probability that an observation will occur. (4 points)
Assume that a normal distribution of data has a mean of 14 and a standard deviation of 2. Use the empirical rule to find the percentage of values that lie below 18.
Suppose X has a normal distribution with mean 80 and standard deviation of 10. Between what values of x do 95% of the values lie? a)50 and 110 b)60 and 90 c)60 and 100 d)75 and 85
A normal distribution has a mean of 80 with a standard deviation of 20. What score separates the highest 40% of the distribution from the rest of the scores? A) X= 54.4 B) X= 85 C) X= 75 D) X= 105.6
The mean of a normal probability distribution is 500; the standard deviation is 14. a. About 68% of the observations lie between what two values? Value 1 Value 2 b. About 95% of the observations lie between what two values? value a Value 1 Value 2 c. Practically all of the observations lie between what two values? Value 1 Value 2
Assume that a normal distribution of data has a mean of 20 and a standard deviation of 5. Use 68 - 95 - 99.7 rule to find the percentage of values that lie above 15. What is the percentage of values lie above 15?
suppose he has a standard normal distribution with a mean of zero and standard deviation of one the probability that Z values are greater than ______ is .3483
1.A distribution of values is normal with a mean of 6.3 and a standard deviation of 83.3. Find P57, which is the score separating the bottom 57% from the top 43%. P57 = 2.A distribution of values is normal with a mean of 180.3 and a standard deviation of 20.5. Find P71, which is the score separating the bottom 71% from the top 29%. P71 =