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Draw the alkene formed when 1-heptyne is treated with one equivalent of HBr

Draw the alkene formed when 1-heptyne is treated with one equivalent of HBr
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Answer #1
Markovnikov tells us that the H atom will bond to the C atom with the larger number of H atoms already attached.

CH=;C-CH2-CH2-CH2-CH2-CH3 + HBr ---> CH2=CBr-CH2-CH2-CH2-CH2-CH3
(Triple bond shown as =; as unable to draw on here)
answered by: Carterita
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