Question

When solutions of AgNO3 and NaOH react, the balanced molecular equation is
2AgNO3(aq) + 2NaOH(aq) Ag2O(s) + 2NaNO3(aq) + H2O(l)

How much Ag2O is produced when 0.200 g of AgNO3 and 0.200 g of NaOH react?

Answer 1

calcualate the moles of AgNO3 and moles of NaOH you started with.

Examine the balanced equation, those two react on a one to one mole ratio, so which was the lowest number? that is the most you can produce. So the balanced equation says you get half that (in moles).

Answer 2

0.136425g

Answer 3

Ans b) 0.136 g

Number of mol of AgNO3 = mass / molar mass

= 0.200 / 169.9 = 0.0012 mol

mol NaOH = 0.200 / 39.997 = 0.005 mol

Number of mol of AgNO3 is less , so it is the limiting reagent here

Number of mol of Ag2O formed = 0.0012 /2 = 0.00059

Mass of Ag2O = mol x molar mass

= 0.00059 x 231.7

= 0.136 grams