f is proportional to velocity
V = [RT/M]^0.5
Sof1/f2 =√M2/√M1 =√4/√28.8 =0.37267
So, f2 = f1/0.37267 =727.169 Hz
A certain organ pipe, open at both ends, produces a fundamental frequency of 271 Hz in air. If the pipe is filled with helium at the same temperature, what fundamental frequency f He will it produce? Take the molar mass of air to be 28.8 g/mol and the molar mass of helium to be 4.00g/mol .
A certain organ pipe, open at both ends, produces a fundamental frequency of 297 Hz in air. If the pipe is filled with helium at the same temperature, what fundamental frequency fHe will it produce? Take the molar mass of air to be 28.8 g/moland the molar mass of helium to be 4.00 g/mol .
A certain organ pipe, open at both ends, produces a fundamental frequency of 280Hz in air. If the pipe is filled with helium at the same temperature, what fundamental frequency f_He will it produce? Take the molar mass of air to be 28.8g/mol and the molar mass of helium to be 4.00g/mol . I have already tried 877Hz and it is incorrect!
A certain organ pipe, open at both ends, produces a fundamental frequency of 297 Hz in air. Part A If the pipe is filled with helium at the same temperature, what fundamental frequency fHe will it produce? Take the molar mass of air to be 28.8 g/mol and the molar mass of helium to be 4.00 g/mol. Express your answer in hertz. V ALD O O ? file Submit Request Answer
A certain organ pipe, open at both ends, produces a fundamental frequency of 290 Hz in air. If the pipe is filled with helium at the same temperature, what fundamental frequency f_He will it produce? Take the molar mass of air to be 28.8 g/mol and the molar mass of helium to be 4.00 g/mol Express your answer in hertz. Now consider a pipe that is stopped (i.e., closed at one end) but still has a fundamental frequency of 290...
Part A: A certain organ pipe, open at both ends, produces a fundamental frequency of 300 Hz in air. If the pipe is filled with helium at the same temperature, what fundamental frequency fHe will it produce? Take the molar mass of air to be 28.8 g/mol and the molar mass of helium to be 4.00 g/mol. I calculated this correctly to be 879 Hz, but I am not sure about the next part. Now consider a pipe that is...
11. Consider an open PVC pipe that is 5 m long and has a fundamental frequency of 70 Hz, open at both ends. a) If the pipe is cut in half, what is the new fundamental fre- quency? (include units) b) If after being cut in half in a), the pipe is closed off at one end, what is the new fundamental frequency? (include units) c) The speed of sound in helium is approximately 3 times faster than in air....
Organ pipe A with both ends open has a fundamental frequency of 320.0 Hz. The third harmonic of organ pipe B with one end open has the same frequency as the second harmonic of pipe A. Assume a speed of sound of 343 m/s. What is the length of Pipe A? What is the length of Pipe B?
Calculate the length of a pipe that has a fundamental frequency of 316 Hz. (Take the speed of sound in air to be 343 m/s.) Calculate the length of a pipe that has a fundamental frequency of 316 Hz. (Take the speed of sound in air to be 343 m/s.) (a) Assume the pipe is closed at one end (b) Assume the pipe is open at both ends
What should be the length of an organ pipe, open at both ends, if the fundamental frequency is to be 264.8 Hz? Assume the initial temperature is 20 degree C. What is the fundamental frequency of the organ pipe of part (a) if the temperature drops to 0.0 degree C?