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Curl and Divergence of a Vector Field

How do I find the curl and divergence of the vector field F(x,y,z) = {1/√(x2+y2+z2)}*(xi +yj+zk) ?
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Answer #2

F (9,7, 3) – xâyſ+ 24 2 2 2 x + y + 2 √ 2 ² + y² +2² 2 2 x+y+2 2. 2 x + y + 2 2 Now curl (F) = 8 x y Z ә 2 ә d а d Әз әу ә2 2у Z Э 2 + d ay əz 2 2 2 x + y + z 2 2. x + il B)- ә Z 1 + 22 √2 + y² 2² (22+y+2? 2 2 2 2 +4 + 2 У? Y Z + - + (22+y%22% roke +Again a X Vazy?+22. 22 () -2. Va Val+y+2? (x² + y² + 2² 2x Ja² 2 2 at y7Z ) 2 2 Va+y?+ 2? - Vax +y273 (72+y2+22) 74722_1 (x²Therefore div (F) = 3. al E x . ә у y - + + 2 ay (x² + y ² 2² x 2 + y 2² Z ola 2 2 x + 4 +2² 2 - + %2 2 all +2 2² 2² 23+y2 (2

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Answer #1
Simplify
answered by: pollito
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