Question

physics

The coefficient of static friction between the m =3.20 kg crate and the 35.0°incline of Figure P4.41 is 0.340. Whatminimum force must be applied to the crate perpendicular to the inclineto prevent the crate from sliding down theincline?
N


Figure P4.41

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Answer #1
To make the crate stop, all forces (gravitational, frictional) mustbe equal to zero. Since the force is perpendicular to the incline,the normal force willbe increased:
mgsinθ - μ(mgcosθ + F) = 0
(3.20)(9.8)sin35.0 - (0.340)(3.20)(9.8)cos35.0 - 0.340F = 0
F = 27.2153832 or 27.22N
answered by: Byron
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