Mass of water=πr2hρ=196.35g
Total heat provided by water to ice=mCpΔT=8219J
Total heat needed to melt ice=mL=16700J
Extra heat required=8481J=2026Cal
Heat flow rate=2026/3600Cal/s=0.5628Cal/s
A glass tumbler of 200 g mass and 5 cm inside diameter is filled to a depth of 10 cm with tap water whose temperature is 10 degrees C, and at 50 g of ice 0 degrees C are then added
m. 11. A glass of 200 g and a 5 cm inside diameter is filled to a depth of 10 cm with tap water of temperature 10" and then 50 g of ice at 0° is added. At the end of an hour vou notice that the ice has just finished melting. What is the average rate in J/s that heat flowed into the glass from its surroundings
An ice cube of mass 8.5 g at temperature 0∘C is added to a cup of coffee, whose temperature is 90 ∘C and which contains 130 g of liquid. Assume the specific heat capacity of the coffee is the same as that of water. The heat of fusion of ice (the heat associated with ice melting) is 6.0 kJ/mol. Find the temperature of the coffee after the ice melts.(in C)
An ice cube of mass 9.0g is added to a cup of coffee, whose temperature is 90.0 °C and which contains 120.0 g of liquid. Assume the specific heat capacity of the coffee is the same as that of water. The heat of fusion of ice (the heat associated with ice melting) is 6.0kJ/mol. Find the temperature of the coffee after the ice melts. Use the equation given in the lab manual on page 86. Ignore the + (CC) (AT)...