show the equation Ax=b does not have a solution for all possible b, and describe the set of all...
A=1 -2 -1
-220
4 -13
and
b = b1
b2
b3
Homework Answers
| Row Operation 1: |
| add 2 times the 1st row to the 2nd row |
|
| Row Operation 2: |
| add -4 times the 1st row to the 3rd row |
|
| Row Operation 3: |
| multiply the 2nd row by -1/2 |
|
| Row Operation 4: |
| add -7 times the 2nd row to the 3rd row |
|
| Row Operation 5: |
| multiply the 3rd row by 1/6 |
|
b1
2b1+b2
b3
=>
b1
2b1+b2
-4b1+b3
=>
b1
b1+b2/2
-4b1+b3
=>
b1
b1+b2/2
-4b1+b3+-7b1-3.5b2
=>
b1
b1+b2/2
-11b1-2.5b5 /6
thus
-11b1-2.5b5 /6 =0
system does not have solution
hence the augumented matrix |A|b| should be equal to zero. so that Ax=b doesn't have a solution.
and to have a solution augumented matrix |A|b| should not be equla to zero.
hope this is the answer.
Add Answer to:
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