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eaklast on a weekday 2 and σ 12. According to Chebyshevs UAbility can we assert that between 94 and 190 customers Ill Have b
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Answer #1

Solution:

Given: A student answers the 144 questions on a true false test by flipping a balanced coin.

A balanced coin means fair coin, that is Probability of head = probability of tail = 0.5

thus p = 0.5 and q = 0.5

Part a) Find mean \mu and standard deviation \sigma by using formulas of Binomial distribution.

\mu = n \times p

μ = 144 × 0.5

\mu = 72

and

\sigma = \sqrt{n \times p \times q}

σ = V144 × 0.5 × 0.5

\sigma = \sqrt{36}

\sigma = 6

Part b) We have to find values of number of correct answers that student will get using Chebeshev's theorem with probability of at least 0.96

According to Chebeshev's theorem, at least 172 162 of the data lie within k standard deviations from the mean of the distribution.

that is:

k:2 1.2

So we have

|-읊) = 0.96 12

(1-0.96) = 1.2

0.04 =

0.04

k- 25

5

Thus we get:
μ-k σ 72-5 × 6-72-30-42

and

μ + k σ = 72 5 × 6 = 72 + 30 = 102

Thus there is at least 0.96 probability that student can answer correct answers between 42 and 102 out of 144.

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