Question

The following table indicates the driving distances, in yards, from a random sample of drives for the pro golfers Phil Mickelson, Tiger Woods, and Jim Furyck. Perform a one-way ANOVA using α = .05 to determine if there is a difference in the average driving distances of these three players 3. Mickelson Woods Furyck 290 295 288 327 Anova: Single Factor 311 290 297 286 266 265 285 279 280 SUMMARY Count SurT Coimn Column 2 Column 3 1200 1184 1375 300 332.66667 296 120.66667 275 80.5 ANOVA Source of VariationSS Between Groups 1659,692308 MS р.volue Fenit 0.0323071 1 ‘[O Within Groups82 Total 3341.692308

Answer 1

ANOVA tuble ouce ss d. d f ccultulate alue bekoeer) 659.692308 | p-1 aoups ssA) 379.3J mSA 8.8 D o 32 367 68.2 mSE) 4.9371 ce Oyou ps F, Tot 3341.9230-l SS T) -13-1 -12

ら dentity nul \ anc aHeY native hypothesis To lest al Is there any difference i ge drivi distante of these player ave ya dYIvIn Versu ive hyrothehts H1Not all u's are same tevel d sianitica nte 0.05. 3 et F 4.10 1821 Test statytic mS (bet soup) cal MIS (within aou 829.3 S 163-2 Fccel= 4.333687 Sinte,

⑥ Concluuico :- S ince, Fekedurd Feritices or ngject Mo at Enu , *sero 5% level (f significance Trui, not al l average ơfchiving distance 64 there thee pe player an some To check cohich pair dre different uoe have thte playens say A,B andc ie. (A, B), (6, C) and (a, pa uwe we mstiple comparlison test Thw we have ttmee paiys use had to do pairco ise §com paison ..fe버 firstty def initton Ho rth and th pair Vs Hı :.u;一.ujto.

test statistic Yi - t-distrbutuan n. tohere somple meon thplaye ond th player upertively MSE Sa , n4 and s 168. -3,-275 , n325 20 02 5

Table 2 )300-296) 25 1 296- 275 682( Note, see table value to.es,(atur2to ,6 Now, sinte, we accept Ho uie u2

nd and 2 signrficance 下ht) , Conclusion :- Coneusion, T, (A, B) and a twooups e. Average divig distante Playey B is sane, and that ofC i diterent A ac signifirance. A and B at 5% level