Question

2. Consider the four-pole two-phase permanent-magnet ac machine with the parameters r: 3.40 Lss-121mH, and Am-0.0826 V . the rotor is driven at arm- s/rad, The stator windings are short circuited and 100 T. Calculate igs, Ids and las.

Answer 1

Ans: Given that:

r_s =3.4 ohm, L_ss=12.1mH and$\lambda$_m=0.0826 V.s/rad ,w_e==104.71 ,let i=1A

100π

V_r=$\lambda$_m*w_rm = 104.71 v

to find i_qs:

i_qs= $\frac{-1}{r}(w_{e}-w_{r})\lambda _{ds}$ =2.4A

wr=w_{e+$\frac{r.i}{}L_{ss\lambda _{m}}$}= 3.401

for i_as

stator windind is short circuit hence i_as=0

for i_ds

i_ds=$\frac{-1}{r}(w_{e}-w_{r})\lambda _{qs}$=360.57A

$\lambda _{qs}=L_{ss}*i$=12.1