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Given that the reflectance and transmittance for a plane wave polarised perpendicular to the pl n by: ane of incidence are gi

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Answer #1

For parallel polarization, the reflectance is:

R_p = r_p^2 = \left( \frac{n_1cos\theta_2-n_2cos\theta_1}{n_1cos\theta_2+n_2cos\theta_1}\right )^2

From Snell's law, \theta_2 = sin^{-1}\frac{1sin30}{1.5} = 19.47\degree

so, Rp = 0.0252

therefore, Tp = 1 - Rp = 0.9748

Degree of Polarization for reflected light is:

P_{ref} = \left|\frac{R_s - R_p}{R_s+R_p}\right|\times 100\%

similarly, Degree of Polarization for transmitted light is:

P_{tra} = \left|\frac{T_s - T_p}{T_s+T_p}\right|\times 100\%

substitute the values of Rs,Rp,Ts and Tp to get the degree of polarizations for both reflected and transmitted light.

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