This is a decision tree and we need to find the expected values at each node to finalize a path/option. The node with max expected values should be taken (purely on financial grounds).
Now, lets see how to calculate expected value. Consider following exampl
Here, p represents the probability of the outcome. From Node 1 we can go to node 2 or node 3 and both have probabilities of 0.5.
Expected value of node 1, EMV (node 1) = [ probability (node 2) * value of node 2 ] + [ probability (node 3) * value of node 3 ]
= [ 0.5 * 200 ] + [ 0.5 * (-100) ] = 100 - 50 = $50
Coming back to the question, probability is not given. We can also choose probabilities as 0.6 for success and 04 for failure, which is seen in top most line of image of the question.
Now, using above logic we can calculate expected value of nodes 4,5,6,7,8,9 in the question as follows.
Please note that
EMV (node 4) = EMV (node 7), EMV (node 5) = EMV (node 8) and EMV (node 6) = EMV (node 9), because outcomes are same and hence considering same probability will give same result.
EMV (node 4 or node 7) = (0.6 * 50000) + ( 0.4 * 30000) = $ 42,000
EMV (node 5 or node 8) = (0.6 * 100000) + ( 0.4 * (-40000)) = $ 44,000
EMV (node 6 or node 9) = (0.6 * 30000) + ( 0.4 * 10000) = $ 22,000
Now max of these 3 gives us: $44,000
From this result we can see that option 2 (Office building) is the way to go.
If we consider probility as 0.5 of each node, then
EMV (node 4 or node 7) = (0.5 * 50000) + ( 0.5 * 30000) = $ 40,000
EMV (node 5 or node 8) = (0.5 * 100000) + ( 0.5 * (-40000)) = $ 30,000
EMV (node 6 or node 9) = (0.5 * 30000) + ( 0.5 * 10000) = $ 20,000
In this case max = $40,000 which is option 1 (Appartment building)
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