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Consider an NACA 23012 airfoil. The mean camber line for this airfoil is given by -= 2.6595 | 0.6075 | + 0.1 147 ( for0 s-s 0
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Let--(1-cos θ) When -=0.2025 →0.2025 =-(1-cos θ) Differentiate with respect to x →cos θ = 0.595 →θ=0.9335 rad +0.1147 |-0.607.2.6595| 3.1 2(1-cosej-0.6075. 21 2(1-cos θ)-0.1147 ах = 2.6595| 4.(1-2cose+ cos2 θ)-0.6075(1-cos θ) +0.1147 -0.6840-2.3736 cCalculate the angle of attack at zero lift 1 09335 dz 1109335[ LÍO3 [ 0.6840-2.3736 cos θ +1.995 cos* θ | ( cos θ-1) dθ_ 1193Calculate A 2 09335 dz -,0933s( 2C9335( 0.6840-2.3736 cos θ + 1 .995 cos* e) cos&d + -0.02208 ) cosAdθ 0.0954 Calculate A 2 r

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