This is a simple problem related to linear optimization modeliing.
From the excel sheet model provided to us, we can infer that
1. The objective function is 3X1+5X2+4X3 which is needed to maximized.
2. The constraint functions are
1. for cutting and sewing :12X1+10X2+8X3<=18000
2. For sewing : 15X1+15X2+12X3<=18000
3. For inspection and packaging : 3X1+4X2+2X3<=9000
4 . For all pro model s: X1>=1000
Aslo all variables should be non negative
X1,X2,X3>=0
Now we are sorted . We have the subjective function and the constraints given as well.
Now we shall try to find the optimal values of each of X1,X2, and X3.
I seeked solution of the given LP model with the help of simplex method and got the following results.
There are infinitely many values of X1, X2, X3 for the optimal
value Z = 4000, which are contained in the part of the plane 3 X1 +
5 X2 + 4 X3 = 4000 that satisfy the constraints of this problem.
One of them is:
X1 = 1000
X2 = 200
X3 = 0
1. Thus the maximized profit will be $4000 and to make it happen we must have 1000 All pros ,200 collage and nil HS balls.
Q2. Overtime rates in the sewing department are $12 per hour. Which of the following is correct?
Look at the constraints associated with overtime on sewing machines.
In the sewing department all of the production time is used .Thus If the production time at sewing department is increased by one minute, the profits will increase by $0.333. If the production time at sewing department is increased by one hour, the profits will increase by $0.333(60) = $20. So, management would be willing to pay $12 per hour for overtime work at the sewing department.
Hence overall profit per hour will be $(20-12)=$8
Hence we can say that option c is correct.
Q3. If College football profit was $3 more (i.e. $8), which of the following is correct.
Reflect back on the objective function.
3X1+5X2+4X3
Here what we are essentially doing is that we are increasing the profit by 3$ to $8 for collage balls.
This will actually change hte coeffifcnet of college balls (X2) from 5 to 8.
We run the optimal solution and get
There is any possible solution for the problem, so we can continue to Phase II to calculate it.
The optimal solution value is Z = 4600
X1 = 1000
X2 = 200
X3 = 0
The overall profit increases by $600 while the number of balls of each type remain the same. (no change on optimality)
Hence option (b).
Q4. All-Pro football constraint has negative $2 shadow price. What does it mean?
This means that there is a reverse relationship between the ball requirmenets and profit.
Hence
an increase of one in All-Pro requirement will reduce profit by $2
Hence option (b).
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