Question

please provide a complete a detailed solution and the correct answer. THANK YOU

33.In the k-nearest-neighbor classifier below, the vector to be classified is denoted by the symbol, and for a k-4 nearest neighbor classifier the resulting classification would be д) Triangle b) Square c> unclassified d)none above 91 Cs Scanned with CamScanner Vector to be classified G (81.821 92

Answer 1

In KNN, K is the number of nearest neighbors. The number of neighbours is the core deciding factor. Generally k can be taken odd number of values

In this algorithm classifiy the points by majority vote of it's k-neighbors

So here, K=4 it is even so, the nearest neighbor classification would be not decided so, option C is correct.