Question

Suppose that the time T (in days) for a cancerous tumor to double in volume (in cm3) is given by 10 1n 2 where Vo is the volume of the tumor when it's first observed and Vi denotes its volume 10 days later. Assume that 。s conecty measured to be 21 cm3 and Vi is measured to be 33 cm3 with a measurement error of at most 0.4 cm3. Estimate the error in the computed value of T Round your answer to two decimal places. The error in the computed value of T is days the absolute tolerance is +/-0.01

Answer 1

Vo=210m3 Nwammad to be 33 eroy o mo st +04 cm2 ie. , e [33-04, 3340.4) , Loh , Vf= 3 15.33561934 Qn 33- 21 R 15.336 Va = 33-04-32. 6, tha, T= 15.4603726.. ~ 15-461 111.931 vg- 33 +0.4 33.4 ,Hun T = 14.937 4376.. ~ V1 E T33.04, 334041 , TE [14.937, 15.761. [14.94 ,15.飞 and -33 , T15.3315 3 i.e , 유 V1EL33-64.33+0.4] , TE [15.34-0.40 ,15.34 +0.40 and 10.4 0.41 1042-0-41] $ 0,01