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Suppose that a dog can successfully shake a paw with independent and constant probability p. In a...

Suppose that a dog can successfully shake a paw with independent and constant probability p. In a particular training session, let X be the number of paw shakes until the dogs first failure. Let Y be the number of paw shakes until the dogs second failure. Show that
P(Y=2X) = (1-p) / (1+p)

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Answer #1

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