Homework Answers
Add Answer to:
Figure 3 shows a cross-section of a combined open and closed section beam with a thickness of 2 m...
Z = 13*100mm PROBLEM: A thin-walled cantilever beam of unsymmetrical cross-section is subjected to a uniform...
Z = 13*100mm
PROBLEM: A thin-walled cantilever beam of unsymmetrical cross-section is subjected to a uniform distributed load was shown in the figure below. The wall thickness t can be assumed to be very small in comparison with hin calculating the sectional properties. Determine the stress distribution on the cross section and the position of the neutral axis. Find the deflection of the beam at the cross section. Use:w=0.8N/mm: L = 1500 mm; h = 80 mm: t= 2 mm:...
10 mm 10 mm 300 N/m 50 mm 10 mm Problem 2. Consider the beam above with the cross-section shown. ...
please solve 1-5 and show all steps and equations used
10 mm 10 mm 300 N/m 50 mm 10 mm Problem 2. Consider the beam above with the cross-section shown. The number (300N/m) indicates the value of the load distribution at its peak. (5 pts.) Find the reactions (15 pts.) Draw the shear and moment diagrams using the graphical method. Ensure you state values of the diagrams, and type of function for lincar or higher-order segments. You can indicate all...
Question 3 For the simply supported steel beam with cross section and loading shown (see Figure...
Question 3 For the simply supported steel beam with cross section and loading shown (see Figure 3a), knowing that uniformly distributed load w=60 kN/m, Young modulus E = 200 GPa, and yield stress Cyield=200 MPa (in both tension and compression). ул 15 mm w=60 kN/m ... 1 B A 15 mm + 300 mm IC - i 2.5m 1 1 15 mm 7.5m 1 150 mm Figure 3a (a) Check if: the beam is safe with respect to yielding (using...
Question 2 The single-cell thin-walled beam of Figure 2 with all dimensions in mm has a...
Question 2 The single-cell thin-walled beam of Figure 2 with all dimensions in mm has a constant torque T-3150 Nm applied to it. The shear modulus for all skin section is 27.5 GPa. Determine (a) the shear flow distribution, (b) the maximum shear stress, and (c) the rate of twist. 13 225 75 3150 N.m 400 Fig. 2
Question 1 (Total 100/3 Marks) Figure 1 (all units are mm) shows a simply supported beam of span ...
Question 1 (Total 100/3 Marks) Figure 1 (all units are mm) shows a simply supported beam of span 2500 mm with a 5 kN/m load. The cross-section of the beam is a composite section made from two steel plates attached to the top and bottom of a timber section. The top steel plate is 5 mm wide and 20 mm deep. The bottom steel plate is also 5 mm wide but 10 mm deep. The timber section is 50 mm...
As shown in Figure 8, the structural member (beam) is 7m long, carries a 2 kN point load, a 1.2 kN/m uniformly distribu...
As shown in Figure 8, the structural member (beam) is 7m long, carries a 2 kN point load, a 1.2 kN/m uniformly distributed load and is supported at points A and B. The beam is constructed from two pieces of steel plate (2 at 80mm x 8mm) that are welded together with 3mm welds. Section properties for the beam are also listed. Given the support reactions as RAv 5.8 kN and RBv 2.2 kN, as well as the shear force...
x7=12KN , x8=19kN/m, x4=4m, x5=39m, x6=5m, Q2. In the 3-span beam shown in the Figure 2, the...
x7=12KN , x8=19kN/m, x4=4m, x5=39m, x6=5m,
Q2. In the 3-span beam shown in the Figure 2, the support at C settles by 15 mm. Using the method of moment distribution method, a) Calculate joint moments (10 marks); b) Draw the bending moment diagram (10 marks); c) Calculate the supports' vertical reactions (10 marks); and d) Draw the shear force diagram (5 marks). Hint: For the calculation of Fixed End Moments, you can use the principle of superposition to add the settlement-related...
Z = 13*100mm
PROBLEM: A thin-walled cantilever beam of unsymmetrical cross-section is subjected to a uniform distributed load was shown in the figure below. The wall thickness t can be assumed to be very small in comparison with hin calculating the sectional properties. Determine the stress distribution on the cross section and the position of the neutral axis. Find the deflection of the beam at the cross section. Use:w=0.8N/mm: L = 1500 mm; h = 80 mm: t= 2 mm:...
please solve 1-5 and show all steps and equations used
10 mm 10 mm 300 N/m 50 mm 10 mm Problem 2. Consider the beam above with the cross-section shown. The number (300N/m) indicates the value of the load distribution at its peak. (5 pts.) Find the reactions (15 pts.) Draw the shear and moment diagrams using the graphical method. Ensure you state values of the diagrams, and type of function for lincar or higher-order segments. You can indicate all...
Question 3 For the simply supported steel beam with cross section and loading shown (see Figure 3a), knowing that uniformly distributed load w=60 kN/m, Young modulus E = 200 GPa, and yield stress Cyield=200 MPa (in both tension and compression). ул 15 mm w=60 kN/m ... 1 B A 15 mm + 300 mm IC - i 2.5m 1 1 15 mm 7.5m 1 150 mm Figure 3a (a) Check if: the beam is safe with respect to yielding (using...
Question 2 The single-cell thin-walled beam of Figure 2 with all dimensions in mm has a constant torque T-3150 Nm applied to it. The shear modulus for all skin section is 27.5 GPa. Determine (a) the shear flow distribution, (b) the maximum shear stress, and (c) the rate of twist. 13 225 75 3150 N.m 400 Fig. 2
Question 1 (Total 100/3 Marks) Figure 1 (all units are mm) shows a simply supported beam of span 2500 mm with a 5 kN/m load. The cross-section of the beam is a composite section made from two steel plates attached to the top and bottom of a timber section. The top steel plate is 5 mm wide and 20 mm deep. The bottom steel plate is also 5 mm wide but 10 mm deep. The timber section is 50 mm...
As shown in Figure 8, the structural member (beam) is 7m long, carries a 2 kN point load, a 1.2 kN/m uniformly distributed load and is supported at points A and B. The beam is constructed from two pieces of steel plate (2 at 80mm x 8mm) that are welded together with 3mm welds. Section properties for the beam are also listed. Given the support reactions as RAv 5.8 kN and RBv 2.2 kN, as well as the shear force...
x7=12KN , x8=19kN/m, x4=4m, x5=39m, x6=5m,
Q2. In the 3-span beam shown in the Figure 2, the support at C settles by 15 mm. Using the method of moment distribution method, a) Calculate joint moments (10 marks); b) Draw the bending moment diagram (10 marks); c) Calculate the supports' vertical reactions (10 marks); and d) Draw the shear force diagram (5 marks). Hint: For the calculation of Fixed End Moments, you can use the principle of superposition to add the settlement-related...
Most questions answered within 3 hours.
-
a. What double precision floating point
number is represented by the following 64-bit binary? Show your...
asked 6 minutes ago -
Indicate whether the statement is true or false
(1-20).
1)A good time management plan will eliminate...
asked 34 minutes ago -
Which one of the following will occur when the internal rate of
return equals the required...
asked 1 hour ago -
The mean value of land and buildings per acre from a sample of
farms is $1800,...
asked 1 hour ago -
The Hotel Conneautis considering 3 the
following capital budgeting projects
The Hotel Conneaut has internal funind for...
asked 1 hour ago -
Which of the following is NOT a product of the first step in the
p-p chain...
asked 1 hour ago -
The chance that UPS will deliver a package to a customer within
X days is normally...
asked 1 hour ago -
3Cu(NO3)2(aq) + 2Al(s) ---> 3Cu(s) + 2Al(NO3)3(aq) if you
have 32 moles of aluminum, what is...
asked 1 hour ago -
Four 100 micro Farads capacitors are connected in parallel, the
equivalent capacitance of these four capacitors...
asked 1 hour ago -
What is the pH of a 3% solution of atropine sulfate knowing that
the molecular weight...
asked 1 hour ago -
A company has current assets of
$90,000 and its current ratio is 2.5. Assume that the...
asked 1 hour ago -
A firm should never accept a project if its acceptance would
lead to an increase in...
asked 1 hour ago