Question

MATLAB only please

Objective Using repetition to find an optimal solution Project A company wants to locate a distribution center that will serve six of its major customers in a 30r30 square mile area. The location of customers relative to the southwest corner of the region is given in the following table where r is the coordinate east of the origin and y is the coordinate north of the origin. Volume customer (miles) (miles) (tons/week) y1 y1 y1 y1 4 8 y1 Table 1: Customer Location and Purchase Volume The delivery cost depends on the volume that the customer orders, V, and the distance from the distribution center. For simplicity assume that the distance for customer i, di, is the straight line Euclidean distance between two points. The cost for each customer is c0.5d,V Write a MatLab oode that will determine the location of a distribution center that minimizes the total weekly cost to service all six customers This program will prompt the user for the locations and volume ordered for each customer. The location values must be error checked to be between 0 and 100 for r and 0 and 75 for y. The volumes must not be negative To perform the optimization, you should write a set of nested for loops. The first will start at r- 0 and proceed to r-100. The second nested inside the r loop - will start at y 0 and prooeed to y 75. At each step the program will calculate the six distances and the six costs that would occur if the distribution is built there. If that (,y) location is the current minimum cost then it should replace any previous optimal location and cost. Once all 7500 possible locations have been evaluated the current minimum cost would be stored in the minimum locations

I am trying to get my getdatafuntion to work. I am also trying to get all my x's, y's, and v's to popup in the command window so I can put in any value and it will find the value for me using

the equation I put in.

function project_9_sjl()
% PROJECT_9_SJL project_9_sjl() is the driver function for the program.
%
%    Name: Scott Lawrence
%   Date: 3/27/2019
%   Class: CMPSC 200
%   Description: Determine the optimal location of a warehouse
%
   fprintf('\t\tAUTHOR: Scott Lawrence\n');
fprintf('\t\tDATE: 27 March 2019\n');
fprintf('\t\tDESCRIPTION: Determine the optimal location of a warehouse\n');

  
  
[X1, X2, X3, X4, X5, X6, Y1, Y2, Y3, Y4, Y5, Y6] = getLocations();


function x = getDataRange
x = input('Enter the location of X1');
if x > 100, x < 0;
fprintf(Inputvalue)
getDataRange
  
else
  
end
end
  
   %   Enter the locations of the customers
function [X1, X2, X3, X4, X5, X6, Y1, Y2, Y3, Y4, Y5, Y6] = getLocations()
  
X1 = getDataRange('Enter the location of X1:', 0, 100);
X2 = getDataRange('Enter the location of X2:', 0, 100);
X3 = getDataRange('Enter the location of X3:', 0, 100);
X4 = getDataRange('Enter the location of X4:', 0, 100);
X5 = getDataRange('Enter the location of X5:', 0, 100);
X6 = getDataRange('Enter the location of X6:', 0, 100);
Y1 = getDataRange('Enter the location of Y1:', 0, 75);
Y2 = getDataRange('Enter the location of Y2:', 0, 75);
Y3 = getDataRange('Enter the location of Y3:', 0, 75);
Y4 = getDataRange('Enter the location of Y4:', 0, 75);
Y5 = getDataRange('Enter the location of Y5:', 0, 75);
Y6 = getDataRange('Enter the location of Y6:', 0, 75);

  
  
end

[V1, V2, V3, V4, V5, V6] = getVolumes()

function v = getDataRange
v = input('Enter the location of V1');
if x >0, x<0;
fprintf(Inputvalue)
getDataRange
  
else

end
  
end
  

   % Prompt the user for the customer volumes
function [V1, V2, V3, V4, V5, V6] = getVolumes()   %   Get the six volumes
  
V1 = getDataRange('Enter the location of V1:', 0, 1e99);
V2 = getDataRange('Enter the location of V2:', 0, 1e99);
V3 = getDataRange('Enter the location of V3:', 0, 1e99);
V4 = getDataRange('Enter the location of V4:', 0, 1e99);
V5 = getDataRange('Enter the location of V5:', 0, 1e99);
V6 = getDataRange('Enter the location of V6:', 0, 1e99);
  
end
  
  
  
   %   Find the optimal location   
  
  

  
   %   Print results from the optimization   
function printResults(X1, X2, X3, X4, X5, X6, Y1, Y2, Y3, Y4, Y5, Y6, V1, V2, V3, V4, V5, V6, xOpt, yOpt, minCost)

  
fprintf('\t\t X1%5.2 \n',X1)
fprintf('\t\t X2%5.2 \n',X2)
fprintf('\t\t X3%5.2 \n',X3)
fprintf('\t\t X4%5.2 \n',X4)
fprintf('\t\t X5%5.2 \n',X5)
fprintf('\t\t X6%5.2 \n',X6)
fprintf('\t\t Y1%5.2 \n',Y1)
fprintf('\t\t Y2%5.2 \n',Y2)
fprintf('\t\t Y3%5.2 \n',Y3)
fprintf('\t\t Y4%5.2 \n',Y4)
fprintf('\t\t Y5%5.2 \n',Y5)
fprintf('\t\t Y6%5.2 \n',Y6)
fprintf('\t\t V1%5.2 \n',V1)
fprintf('\t\t V2%5.2 \n',V2)
fprintf('\t\t V3%5.2 \n',V3)
fprintf('\t\t V4%5.2 \n',V4)
fprintf('\t\t V5%5.2 \n',V5)
fprintf('\t\t V6%5.2 \n',V6)
fprintf('\t\t xOpt%5.2 \n',xOpt)
fprintf('\t\t yOpt%5.2 \n',yOpt)
fprintf('\t\t minCost%5.2 \n',minCost)
  
  
  
end
  
  
end

function [optX, optY, optCost] = findOptimal(X1, X2, X3, X4, X5, X6, Y1, Y2, Y3, Y4, Y5, Y6, V1, V2, V3, V4, V5, V6)
%   FINDOPTIMAL   findOptimal(xLoc, yLoc, shipVolumes) is function that uses
%   a brute force algorithm to find the optimal location of a warehouse.
%  
%   The function returns three values; the optimal x and y coordinates and
%   the minimum cost
%
%   Name:   Scott Lawrence
%   Date:   3/27/2019
%   Class:   CMPSC 200
%  
%

   %   Set a minimum value for the cost - this should be a big number (1e99)?
   optCost = 1.0e99;
  
   %   Set the starting the optimal locations - make it impossible (-1, -1)?
   optX = -1;
   optY = -1;
  
   %   Create two nested for loops that step through all of the possible
   %   (x, y) pairs
   for x = 0:100
  
for y = 0:75
      
       %   Calculate the n distances and n costs
       %  
  
d1 = sqrt((X1 - x).^2 + (Y1 - y).^2);
c1 = sqrt*d1*V1;
d2 = sqrt((X2 - x)^2 + (Y2 - y)^2);
c2 = sqrt*d2*V2;
d3 = sqrt((X3 - x)^2 + (Y3 - y)^2);
c3 = sqrt*d3*V3;
d4 = sqrt((X4 - x)^2 + (Y4 - y)^2);
c4 = sqrt*d4*V4;
d5 = sqrt((X5 - x)^2 + (Y5 - y)^2);
c5 = sqrt*d5*V5;
d6 = sqrt((X6 - x)^2 + (Y6 - y)^2);
c6 = sqrt*d6*V6;
  
totalCost = c1+c2+c3+c4+c5+c6;
  
if totalCost < optCost
  
optCost = totalCost;
  
optX = x;
  
optY = y;
      
  
  
       %   Now check the cost against the current minCost - this is an
       %   simple if. If the new cost is less then change the min cost and
       %   set optX and optY to the new locations (x, y). If it is not
       %   then you don't need to do anything
      
end
end
  
end
  
end

Answer 1

The problem in input values was due to the incorrect definition of datarange() function. Please see the corrected version below:

function x = getDataRange(str,xbl,xul)
x = input(str); % display the message
if x > xul % check if input value exceed the upper limit
fprintf('\nOut of range! Resetting it to upper limit, x=%d\n',xul);
x=xul;
  
elseif x<xbl % check if input value crosses the lower limit
fprintf('\nOut of range! Resetting it to lower limit, x=%d\n',xbl);
x=xbl;
end
end

=========== SAMPLE OUTPUT

Command Window >> project 9_sjl AUTHOR: Scott Lawrence DATE 27 March 2019 DESCRIPTION Determine the optimal location of a warehouse Enter the location of X1:10 Enter the location of X2:10 Enter the location of X3:10 Enter the location of X4:101 Out of range! Resetting it to upper limit, x-100 Enter the location of X5:10 Enter the location of X6:1O Enter the location of Y1:10 Enter the location of Y2:0 Enter the location of Y3:10 Enter the location of Y4:1O Enter the location of Y5 10 Enter the location of Y6:10 Enter the location of V1:100 Enter the location of V2:-5 Out of range! Resetting it to lower limit, x 0 Enter the location of V3:10 Enter the location of V4:4 Enter the location of V5 10 Enter the location of V6:35 V1 =

100 V2 10 10 35 r >