You should be able to do the following problems: Exercise 8.3 Problems 11 - 28 Hand in the follow...
cnrn Consider the following differential equation. (1 + 3x?) y" – 2xy' – 12y = 0 (a) If you were to look for a power series solution about xo = 0, i.e., of the form Σ n=0 00 then the recurrence formula for the coefficients would be given by Ck+2 g(k) Ck, k > 2. Enter the function g(k) into the answer box below. (b) Find the solution to the above differential equation with initial conditions y(0) = 0 and...
: Solve the following differential equation eigenvalue problems. a y'' + λy = 0; y(0) = 0; y(4) = 0 b y''+ λy = 0; y(0) = 0; y' (1) − 2y(1) = 0 In problem [a] you may assume that there are no eigenvalues for λ ≤ 0. In problem [b] you will not be able to find the exact eigenvalues. You should find a condition on the eigenvalues of the form f(µ) = 0 where µ 2 =...
(1 point) In this problem you will solve the differential equation or @() (1) Since P(a) 0 are not analytic at and 2() is a singular point of the differential equation. Using Frobenius' Theorem, we must check that are both analytic a # 0. Since #P 2 and #2e(z) are analytic a # 0-0 is a regular singular point for the differential equation 28x2y® + 22,23, + 4y 0 From the result ol Frobenius Theorem, we may assume that 2822y"...
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11. Make a detailed graph of the function f)-1---on the interval |-4,1] by completing the following steps (a) Compate f(x). (Make sure it is correct before contisuing) (b) Determine those points a Determine those points x for which f(e)-o, that is, compate the eritical pointa of (oeparate multiple points with commas) answer in the form of a sign chart for ) You will lose credit...
This is the sequence 1,3,6,10,15 the pattern is addin 1 more than last time but what is the name for this patternThese are called the triangular numbers The sequence is 1 3=1+2 6=1+2+3 10=1+2+3+4 15=1+2+3+4+5 You can also observe this pattern x _________ x xx __________ x xx xxx __________ x xx xxx xxxx to see why they're called triangular numbers. I think the Pythagoreans (around 700 B.C.E.) were the ones who gave them this name. I do know the...