Solution:-
(a)
Mean every day interest for standard vehicle = 20
Standard deviation of every day interest for ordinary vehicle = 5
Mean day by day interest for mixture vehicle = 15
Standard deviation of day by day interest for normal vehicle = 3
Mean every day interest for tires = 205 + 155
Therefore,Mean day by day interest for tires=175
Difference of day by day request of tires = 5(5^2) + 5(3^2)
= 5(25)+5(9)
= 170
Change of day by day request of tires = 170
Standard deviation = sqrt(170)
So,Standard deviation = 13.04
Normal interest of tires amid the lead time = 175 * 3
Normal interest of tires amid the lead time= 525 tires
Standard deviation of lead time request = 13.04 * sqrt(3)
Standard deviation of lead time request = 22.60
(b)
Normal day by day request, D = 175
Holding cost per unit, h = $0.2 every day
Requesting cost, K = $1,000
Along these lines, ideal request amount, Q = (2*D*K/h)1/2
Q= sqrt(2*175*1000/0.2)
Ideal request quantity,Q= 1,323 tires
The given administration level is 97 percent,
z = Normsinv (0.97)
z= 1.88
Security stock = z * Standard deviation of lead time request
z= 1.88,Standard deviation of lead time demand=22.60
Security stock=43 units
Reorder point, R = normal lead time request + safety stock
Normal lead time request =525
Security stock=43 units
Reorder point, R = 568 tires
Along these lines, the ideal (Q, R) = (1323, 568)
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