Question

40. Pneumatic Freight Pipeline (5 engineers) A freight pipeline involves the use of a fluid moving through a pipeline to transport a solid or a liquid suhstance over a certain distanoe in other words, the moving fluid conveys "freight. The Buid itself in mang cases is merely discharged at the destination Consider the freight pipeline sketched in Figure 11.8. At the inlet, air is moved into the pipeline by a blower. Just downstream is a hogFper from which the substance to be conveyed is fed into the moving air stream The misture then flows through the pipeline until it encounters a sparator The air is discharged to the atmosphere, and the freight is collected at the bottom of the separator, where it can be discharged to a receiver tank The system of Figure 118 is to convey green peas to a packaging machine. Once packaged, the peas will be froaem and sent tomarket. The peas are to be conveyed at a rate of 3 000 kg/hr, which is the maximam capacity of the packaging machine. The path to be followed is as indicated in the figure. FIGURE 11.8. A fright pipeline using air canvy prus. To be designed, selectnd, er determid 1. The properties (particle density and average particle size) of peas 2. The material the pipeline should be made of 3. The air flow rate required to convey the peas at maximum capacity 574 Chapter 11 Projct Descriptions 4. The total pressure drop S. The power requirements of the blower, and the blower type (positive of the system 591 displacement, or rotary, or centrifugal, etc.) 6. The feed hopper and the separator 7. The configuration of the elbows; ie., the radius of each elbow. If the elbows have too sharp a radius, then a relatively high prssure drop will be encountered (Reference: Pneumatic Conceying of Selids by R. D. Marcus, L. S E Klinzing, and F. Rizk, Chapman and Hall, New Yoek, 2990) 1. Windmill Sizing and Feasibility Study (5 engineers) ㄥ

Answer 1

SOLUTION

INPUT CDU A1 AO B1 Bo SUM1 SUMO Cout 0 0) 0) 0 0 0 0

1-0 1 0 1 1 1-0 1 1 1

a) Decoder and external gates: Here, the select min terms from decoder for each output (i.e. SUMO, SUM1 and Cout) and logically OR them as shown below um0 Decd sum1 BOxt 2k+1 cout B1 x1 2k+1 A0 x1 A1 x1 b) ROM:

16B. ROM cout 00100 "00 00 00 +00 00 00 00 08 00 00 00 00D Oc 00.00.00.00 sumo -、sumi c) 16x1 multiplexers:

Cout sum1